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Power, Energy Transfer and Bills

Electrical Power

Every electrical appliance transfers energy. The rate at which it does so is its power. A 100 W bulb transfers 100 joules of energy every second; a 3 kW kettle transfers 3,000 joules every second. The key equations for electrical power are:

$$P = V \times I$$

$$P = I^2 \times R$$

Where \(P\) is power (W), \(V\) is potential difference (V), \(I\) is current (A), and \(R\) is resistance (\(\Omega\)). The second equation comes from substituting \(V = IR\) into the first. It is useful when you know current and resistance but not voltage.

Key Fact

Power: \(P = VI\) and \(P = I^2R\). Both give power in watts (W). Use the first when you know voltage and current; use the second when you know current and resistance.

Energy Transferred

The total energy transferred by an appliance depends on its power and the time it runs:

$$E = P \times t$$

Where \(E\) is energy (J), \(P\) is power (W), and \(t\) is time (s). Energy can also be calculated using the charge that flows: \(E = Q \times V\), where \(Q\) is charge (C) and \(V\) is potential difference (V). This tells you how much energy is transferred to each coulomb of charge as it passes through the component.

For domestic electricity bills, energy is measured in kilowatt-hours (kWh) rather than joules, because joules are impractically small for household use. To calculate energy in kWh: multiply power in kilowatts by time in hours. The cost is then: \(\text{cost} = \text{energy (kWh)} \times \text{price per kWh}\).

Scenario: A household uses the following appliances on one day: a 3 kW electric shower for 0.25 hours, a 2 kW oven for 1.5 hours, and a 0.1 kW television for 4 hours. Electricity costs 28p per kWh. Calculate the total daily cost.

Step 1 — Energy used by each:
Shower: \(3 \times 0.25 = 0.75 \text{ kWh}\)
Oven: \(2 \times 1.5 = 3.0 \text{ kWh}\)
TV: \(0.1 \times 4 = 0.4 \text{ kWh}\)
Step 2 — Total energy: \(0.75 + 3.0 + 0.4 = 4.15 \text{ kWh}\)
Step 3 — Cost: \(4.15 \times 28\text{p} = 116.2\text{p} \approx \text{£1.16}\)

AC, DC and Mains Wiring

Direct current (DC) flows in one direction only. Alternating current (AC) constantly reverses direction. The UK mains supply is AC at approximately 230 V and a frequency of 50 Hz. AC is used for the mains because its voltage can be easily changed using transformers, which is essential for the National Grid.

A UK three-pin plug has three wires with specific colours and roles:

• Live (brown) — carries the AC supply at about 230 V. Always dangerous, even when a switch is open.
• Neutral (blue) — completes the circuit; normally at 0 V.
• Earth (green and yellow) — a safety wire connected to metal casings; provides a low-resistance path to earth if a fault occurs.

A fuse is always connected in the live wire. If current exceeds the fuse rating, the fuse wire melts and breaks the circuit. The residual current device (RCD) provides even faster protection by detecting tiny current imbalances.

Key Fact

UK plug wires: live (brown) at 230 V, neutral (blue) at 0 V, earth (green & yellow) for safety. The fuse is in the live wire and melts if current is too high. The earth wire prevents the casing becoming dangerously live.

Efficiency

Efficiency measures how well a device converts input energy into useful output energy. The equation is:

$$\text{efficiency} = \frac{\text{useful power output}}{\text{total power input}}$$

Efficiency can be expressed as a decimal or multiplied by 100 to give a percentage. An incandescent light bulb might be only 5% efficient — 95% of electrical energy is wasted as heat rather than light. An LED lamp doing the same lighting job might be around 60-80% efficient, which is why the switch to LED lighting has been a significant energy-saving measure. No device is 100% efficient; energy is always lost to the surroundings, usually as heat.

Question: An electric motor has an input power of 800 W. It does useful mechanical work at a rate of 600 W. Calculate its efficiency and state what happens to the remaining 200 W.

Answer: \(\text{efficiency} = \frac{600}{800} = 0.75\) (or 75%). The remaining 200 W (25%) is transferred to the surroundings as heat due to friction in the bearings and resistance in the motor windings. This energy is not useful — it dissipates into the environment and cannot be recovered.

Reducing Energy Use at Home

Understanding power and efficiency helps households make informed decisions about energy use. The biggest energy consumers in a typical home are heating and hot water (including showers and washing machines), followed by cooking, then refrigeration and lighting. Identifying which appliances draw the most power — and for how long — is the first step in reducing energy bills and environmental impact.

For any given task, a more efficient appliance transfers more of the input electrical energy to a useful output. Replacing a 60 W incandescent bulb with an 8 W LED that produces the same brightness reduces the power draw by over 85%. Over hundreds of hours of use, this saving accumulates significantly on an electricity bill. Energy ratings on appliances (from A to G in the UK, with A being most efficient) allow consumers to compare efficiency at the point of purchase. A highly efficient appliance costs more upfront but typically pays back the extra cost through lower running costs over its lifetime.

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